Question

a five digit number n has all digits different and contains digit 1,3,4,5 and 6 only if n is the smallest possible number such that it is divisible by 11 then what is the tens place digits of n ​

Answer 1

the smallest possible number is

41536

10's place digit -3

Answer 2

N = 13456 is the smallest number.

1–3+4–5+6=11–8=3

1–5+3–4+6=1

1–6+3–4+5=—1

3–1+4–5+6=7

3–1+5–4+6=9

3–4+1–5+6=1

4–1+3–5+6=7

4–1+5-3+6=11

Therefore, N=41536 and 1 is in tens place.