Question

A five-digit numbers divisible by 3 is to be formed using the numerals 0, 1, 2, 3, 4 and 5, without repetition. The total number of ways this can be done is
(a) 216
(b) 240
(c) 600
(d) 3125

Answer 1

Answer:

Step-by-step explanation:

0,1,2,4,5 and 1,2,3,4,5

Where the sum of the 5 digits is divisible by 3.

Now let's take 0,1,2,4,5 first .

For the first place we have 4 numbers (0 excluded) ,for the second place we have 4 (now 0 included) ,for third 3 ,for fourth 2 and for fifth 1. Hence the number of choices we have is 4×4×3×2×1=96 .

Now we take 1,2,3,4,5

Here the number of choices we have is 5×4×3×2×1=120

Hence in total we have 120 +96 = 216 choices