a five litre flask contains 3.5 gm of N2,3g of H2 and 8g of O2 at 27 celcius the total pressure extracted by the mixture and partial pressure of oxygen is
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Hey Dear,
◆ Answer -
Total pressure = 9.35×10^5 Pa
Partil pressure of oxygen = 1.24×10^5 Pa
● Explanation -
Moles of N2 -
n(N2) = 3.5 / 28
n(N2) = 0.125 mol
Moles of H2 -
n(H2) = 3 / 2
n(H2) = 1.5 mol
Moles of O2 -
n(O2) = 8 / 32
n(O2) = 0.25 mol
Total no of moles of gases -
n = 0.125 + 1.5 + 0.25
n = 1.875 mol
To calculate total pressure,
PV = nRT
P = nRT / V
P = 1.875 × 8.314 × 300 / 5×10^-3
P = 9.35×10^5 Pa
Partil pressure of oxygen will be -
P(O2) = P × n(O2) / n
P(O2) = 9.35×10^5 × 0.25 / 1.875
P(O2) = 1.24×10^5 Pa
Thanks dear...
Answered by
2
Answer:
9.24
Explanation:
- answer ok
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