Physics, asked by vikasbasa98001, 9 months ago

A five stage pipeline has a clock cycle time of 5ns. If the non-pipeline clock is also of the same duration than what is the speed up for 75% of pipeline efficiency?

Answers

Answered by archanajhaasl
0

Answer:

The speed up for 75% of pipeline efficiency is 3.75.

Explanation:

To answer this query, use the following formula:

\mathrm{S=n\times \eta}                 (1)

Where,

S=speed-up

n=number of the stages

η=efficiency of the pipeline

From the question we have,

The number of stages in the pipeline=5

The efficiency of the pipeline=75%=0.75

We obtain by entering the numbers in equation (1);

\mathrm{S=5\times 0.75=3.75}        (2)

Hence, the speed up for 75% of pipeline efficiency is 3.75.

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Answered by John242
0

Given that A five-stage pipeline has a clock cycle time of 5ns and 75% of pipeline efficiency

We use the following formula:

S=n \times \eta                  (1)

Where,

S=speed-up

n=number of the stages

η=efficiency of the pipeline

From the question we have,

The number of stages in the pipeline=5

The efficiency of the pipeline=75%=0.75

We obtain by entering the numbers in equation (1);

S=5 \times 0.75 \\=3.75         (2)

Hence, the speed up for 75% of pipeline efficiency is 3.75.

To learn more about pipeline efficiency from the given link

https://brainly.in/question/30541773

#SPJ2

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