Physics, asked by Laurvivani2653, 1 month ago

A fix mass of gas occupied 15L at 27degree c . It is compressed at constant temperature until the volume is 3L calculate the the new temperature?

Answers

Answered by priyarawat800
1

Answer:

Assuming the gas behaves as an ideal gas, and that you meant to write "When a [not "what is"] fixed mass of a gas occupying..., then we can use the ideal gas law, which says that:

n*R = p*V/T

For a fixed amount of gas, n is constant, as is R, the universal gas constant. We can therefore write:

p₁*V₁/T₁ = p₂*V₂/T₂

T₂ = p₂*V₂*T₁/(p₁*V₁)

where p₂ = 2p₁, V₁ = 6L, V₂ = 2L, so:

T₂ = 2p₁*2*(300.15 K)/(p₁*6) = 4*(300.15 K)/6 = 200.1 K = -73.05°C

Answered by shashipratapsingh24
0

Answer:

15/27=3/x

5/9=3/x

5x=27

x=27/5

x=5.6 degree c

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