Question

A fixed mass of a gas has volume 750cc at -23°c and 800mm pressure.Calculate the pressure for which its volume will be 720cm^3,the temperature being -3°c.

Answer 1

$\underline\bold{\huge{SOLUTION\:\: :}}$

First of all, let us note the given informations and the one which we have to calculate.

✔ P1 = 800 mm

✔ V1 = 750 cc

✔ T1 = -23 °C = 250 K

✔ P2 = ?

✔ V2 = 720 cc

✔ T2 = -3 °C = 270 K

By using the gas equation,

P1 V1/T1 = P2 V2/T2

Or, (800×750/250) = (P2×720/270)

Or, P2 = 900 mm Hg.

So, the required pressure of the gas is 900 mm Hg.

Answer 2

Answer:

First of all, let us note the given informations and the one which we have to calculate.

✔ P1 = 800 mm

✔ V1 = 750 cc

✔ T1 = -23 °C = 250 K

✔ P2 = ?

✔ V2 = 720 cc

✔ T2 = -3 °C = 270 K

By using the gas equation,

P1 V1/T1 = P2 V2/T2

Or, (800×750/250) = (P2×720/270)

Or, P2 = 900 mm Hg.

So, the required pressure of the gas is 900 mm Hg.