A fixed mass of gas occupies 40cmcube at 0°C.Find the temperature at which its volume becomes 54.7cmcube,assuming that it's pressure remains constant.
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The initial volume of gas (v1) = 40 cm³
The initial temperature (T1) = 0° C = 273 K
The final volume of gas (v2) = 54.7 cm³
According to charle's law
v1/T1 = v2/T2
40/273 = 54.7/T2
T2 = 54.7*273 / 40
T2 = 373.3275 = 373 K (nearly)
T2 = 373 K = 100° C
The final temperature is 100° C
The initial temperature (T1) = 0° C = 273 K
The final volume of gas (v2) = 54.7 cm³
According to charle's law
v1/T1 = v2/T2
40/273 = 54.7/T2
T2 = 54.7*273 / 40
T2 = 373.3275 = 373 K (nearly)
T2 = 373 K = 100° C
The final temperature is 100° C
eweieyeng:
Please show me how you converted 0°C to 273k
0 degree celsius = 0 + 273 = 273 K
Thanks.
welcome
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