Question

A fixed Pulley is driven by a 100kg mass falling at a rate of 8 m in 4 s. It lifts a load of 75 kgf. calculate :
a) the power input to the pulley taking the force of gravity on 1 kg as 10 Newton.
b) the efficiency of the pulley and,
c) the height to which the load is raised in 4 seconds.

Answer 1

Answer:

Effort=E=100kg=100×10=1000N

d=8m, t=4sec

Load=L=75kgf=75×10=750N

(a) Power = E×d/t= 1000×8/4=2000W

(b)MA=L/E =750/1000 = 75/100 = 0.75

VR = d/d =8/8 = 1

Efficiency =MA/VR =0.75/1 = 0.75

(c) Effort goes down in 4 sec = 8 m

Hence the load raised in 4 sec = 8 m

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