A fixed volume of a gas occupies 760 cm3 at 27degree C and 70cm of hg. what will be its volume at S.T.P
Answers
Answered by
10
P1xV1/T1=P2xV2/T2
v2=(760x70x273)/(300x76)
v2=637cm3
v2=(760x70x273)/(300x76)
v2=637cm3
Answered by
17
by gas laws-
P1V1/T1=P2V2/T2
T1=27+273 =300K
P2=76cm
V2=?
T2=273K
(70×760)÷300=(76×V2)÷273
V2=637 cm³
P1V1/T1=P2V2/T2
T1=27+273 =300K
P2=76cm
V2=?
T2=273K
(70×760)÷300=(76×V2)÷273
V2=637 cm³
Similar questions