Question

A flag pole 12 m high casts a shadow 5 m long. Find the distance of the top of the pole
from the far end of the shadow​

Answer 1

the distance of the top of the pole to the far end of the shadow is

$= \sqrt{ {12}^{2} + {5}^{2} } \\ \\ = \sqrt{144 + 25} \\ \\ = \sqrt{169} \\ \\ = 13 \: m$

Answer 2

Given : A flag pole 12 m high casts a shadow 5 m long.

To Find  : the distance of the top of the pole from the far end of the shadow  

1️⃣ 17 m

2️⃣ 7 m

3️⃣ 15 m

4️⃣ 13 m

Solution:

Pythagoras' theorem: square on the hypotenuse of a right-angled triangle is equal to the sum of the squares of the other two perpendicular sides.

Base = 5 m

Height = 12 m

distance of the top of the pole from the far end of the shadow.* = √5² + 12²

= √25 + 144

= √169

=13

the distance of the top of the pole from the far end of the shadow = 13 m

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