Question

A flag pole 18 m high casts a shadow 9.6 m long. Find the distance of the top of the pole from the far end of the shadow.


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Answer 1

Answer:

Step-by-step explanation:

IT IS PYTHAGORAS THEOREM

AB^2+BC^2=AC^2

18^2+9.6^2=AC^2

324+92.16=AC^2

416.16 SQUARE ROOT =AC

AC=20.4m

Answer 2

Answer:

20.4 m

Step-by-step explanation:

Consider a triangle ABC,

Let BC (flag pole) = 18 m & AB (shadow) = 9.6 m

The distance from the top of the pole, C from the far end I.e., A of the shadow is AC.

Now, in right angled triangle ABC

${ac}^{2} = {ab}^{2} + {bc}^{2}$

${ac}^{2} = {9.6}^{2} + {18 }^{2}$

${ac}^{2} = 92.16 + 324$

${ac}^{2} = 416.16$

$ac = \sqrt{416.16}$

$ac = 20.4 \: m$

Hence, the required distance is 20.4 m