A flag pole 21m high casts a shadow 29 m long.Then the distance of the top of the pole from the far end of the shadow is
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Answer:
50m
Step-by-step explanation:
because pole is 21 m and shadow is 29 m that is +8m so 21 +29 is 50 m
Let BC = 18 m be the flag pole and its shadow be AB = 9.6 m. The distance of the top of the pole, C from the far end i.e., A of the shadow is AC. Hence, the required distance is 20.4 m.
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