a flag pole broke in a strom which was originally 81 ft tall . 28 ft was still sticking straight on the ground where it broke, but the remaing piece bent over and touched the ground at some distance away . how far away is the end of the pole from the base of the pole along the ground ??
Answers
a flag pole broke in a strom which was originally 81 ft tall . 28 ft was still sticking straight on the ground where it broke, but the remaing piece bent over and touched the ground at some distance away . how far away is the end of the pole from the base of the pole along the ground ??
Answer:
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Step-by-step explanation:
Check out the attached image. Point P = base of the pole Point Q = point where the pole broke Point R = point where the tip of the pole landed on the ground. We're told that "28 feet are still sticking straight out of the ground", so PQ = 28 is the vertical leg of the right triangle. The horizontal leg is unknown, so we'll call it x, making PR = x. The hypotenuse is QR = 53 because 81-28 = 53. This is the left-over amount after taking off the 28 feet initially out of the ground from the 81 ft pole. In short, we have these three values a = x is one of the legs b = 28 is the other leg c = 53 is the hypotenuse Use the Pythagorean Theorem to find x a^2 + b^2 = c^2 x^2 + 28^2 = 53^2 x^2 + 784 = 2809 x^2 = 2809 - 784 x^2 = 2025 x = sqrt(2025) x = 45 The end of the pole is 45 feet away from the base Answer: 45 feet