Question

A flag pole is put up at a point F. Wires to hold the pole vertically in place are attached at X on the pole TF. One wire is fixed at a point P on the ground so that PF = 2m. The angle of elevation of X from P is 60 degrees. Another wire is to be fixed to the ground at
Q where QF = 2.5 m.

Answer 1

Answer:

:

°

Now for finding height XF we use trigonometric angles

In traingle XPF

°

h= 2×√3=2√3 m

Now In traingle XFQ

By pythagoras theorem

XQ= 4.27

Total length of wire = 0.4+0.4+4.27=5.07 m

Answer 2

Given:

PF =2m

QF = 2.5

Angle between X and P = 60°

To Find:

The length of wire.

Explanation:

Now for finding height XF we use trigonometric angles

In Δ XPF

h= 2×√3=2√3 m

Now In Δ XFQ

By Pythagoras theorem

XQ= 4.27

Total length of wire

= 0.4+0.4+4.27

=5.07 m

5.07m is the length of wire.