A flashlight runs 2 D-cells of 1.5 volts each in series. The bulb is rated for 0.7 amps. What is its resistance?
Answers
Answered by
1
Answer:
thevalueone
Explanation:
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Answered by
2
Answer:
R = 4.29Ω
Explanation
V = 1.5 V(2)
...V = 3V
I = 0.7 A
R = V/I
R = 3V/0.7A
R = 4.29Ω
Therefore, the resistance is equal to 4.29Ω.
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