Question

• A flask containing 2g of an ideal gas as *X* as pressure
of 3 bar at 25°c & 3g of another ideal gas
introduced in the same flask at same temperature
and the pressure observed was 4.5 bar.
calculate the relationship with their molecular weight ​

Answer 1

Answer:

Both have same moleculer mass

Explanation:

Its simple.... Just pv = nrt

V and t gets canceled

Answer 2

》》Answer《《

Explanation:

Both have same moleculer massExplanation:Its simple.... Just pv = nrt

Both have same moleculer massExplanation:Its simple.... Just pv = nrt V and t gets canceled .

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