Question

a flask contains 0.25 NaOH. what mass of NaOH is present per dm3 of solution​

Answer 1

Answer:

molarity = moles of solute/liters of solution

0.25 M NaOH = 0.25 mol NaOH/L

mass = moles (n) × molar mass (M)

n(NaOH) = 0.25 mol

M(NaOH) = 39.997 g/mol

m(NaOH) = 0.25 mol × 39.997 g/mol = 9.999 g = 10. g NaOH (rounded to two significant figures)

Answer 2

Answer:

30g of NaOH is present per dm cube of solution