Question

A flask Contains 1gram of H2, 2 grams of Ne and 1.6 grams of O2 at a pressure of 2 atmosphere at 27°C.Calculate the partial pressure of each gas
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Answer 1

Answer:

1.537

Explanation:

V=2L

T=27°C=300K

1.6g of CH4=1.6/16=0.1moles of CH4

0.5g of H2=0.5/2=0.25moles of H2

For an ideal gas configuration:

PV=nRT

P_CH4=0.1x0.082x300/2

P_CH4=1.23 atom

P_H2=0.25x0.082x300/2

P_H2=0.307

Total=P_CH4+P_H2

Total=1.23+0.307

Total=1.537