a flask contains a solution with an unknown amount of HCl. this solution is titrated with 0.0207 M NaOH. it takes 4.47ml of the NaOH solution to complete the reactions. what is the mass of the HCl?
KartikeyaGokhale:
What is the molarity of the HCl required or the volume for complete titration?
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H Cl + Na OH ===> H2 O + Na Cl
Number of moles in the 4.47 ml of 0.0207 M solution of Na OH :
= 0.00447 * 0.0207 moles
So number of moles of H Cl in the solution mixed is same.
Mass of HCl = molecular mass * number of moles
= 37.5 * 0.00447 * 0.0207 gms
Number of moles in the 4.47 ml of 0.0207 M solution of Na OH :
= 0.00447 * 0.0207 moles
So number of moles of H Cl in the solution mixed is same.
Mass of HCl = molecular mass * number of moles
= 37.5 * 0.00447 * 0.0207 gms
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