Question

A flask of volume 10^3 cc is completely filled with mercury at 0^@C The coefficient of cubical expansion of mercury is 180xx10^(-6)//^(@)C and heat of glass is 40xx10^(-6)//^(@)C. If the flask in now placed in boiling water at 100^@C how much mercury will overflow?

Answer 1

Given :

Volume of flask = 10³cc

Coefficient of cubical expansion of mercury = 180×10⁻⁶°C

Heat of glass = 40×10⁻⁶°C

To find :

The volume of mercury that will overflow

Solution :

• We know the relation ΔV = V₀rΔT

• Volume of flask increased = V₀rΔT

                   =40×10⁻⁶×10³×10² = 4cc

• Volume of mercury increased = V₀rΔT

                   = 180×10⁻⁶×10³×10² = 18cc

• The volume of mercury that will overflow = 18 - 4 cc

            = 14cc

The volume of mercury that will overflow is 14cc