a flat car of mass M is at rest on a frictionlesss floor with a child of mass m standing at its edge is child jumps of from the car towards right with an initial velocity u with respect to car find the velocity of car after its jump
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a flat car of mass M is at rest on a frictionlesss floor with a child of mass m standing at its edge is child jumps of from the car towards right with an initial velocity u with respect to car find the velocity of car after its jump
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Let car attains a velocity of magnitude v leftwards, and the net velocity of the child with respect to earth will be u−v, as u is its velocity with respect to the car. Initially. the system was at rest, thus according to momentum conservation momentum after jump must be zero, as
m(u−v)=Mv
v= m+M/mu
Hence, the velocity of the car after its jump is v= m+M/mu
m(u−v)=Mv
v= m+M/mu
Hence, the velocity of the car after its jump is v= m+M/mu
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