Question

a flat curve on highway has a radius of curvature 400m. a car rounds the curve at a speed of 32 m/s. what is the minimum value of coefficient of friction that will prevent car from sliding. (g-9.8 m/s)

Answer 1

32^2/(400×9.8)=.2612

Answer 2

Answer: Coefficient of friction is 0.2

Explanation :

It is given that,

Radius of curvature, r = 400 m

Speed of car, v = 32 m/s

Let $\mu$ is the coefficient of friction.

We know in a curve the relation between the velocity and the radius of curve is given by :

$r=\dfrac{v^2}{\mu g}$

$\mu=\dfrac{v^2}{rg}$

$\mu=\dfrac{(32\ m/s)^2}{400\ m\times 9.8\ m/s^2}$

$\mu=0.26$

Hence, this is the required solution.