Question

A flat key is used to connect a pulley to a 45mm diameter shaft. The standard cross section

of the key is 14 × 9 mm. The key is made of commercial steel (Syt = Syc = 230 N/mm2)

and the factor of safety is 3. Determine the length of the key on the basis of shear and

compression considerations, if 15kW power at 360rpm is transmitted through the keyed

joint. Using maximum shear stress theory.​

Answer 1

• flat key is used to connect a pulley to a 45 mm diameter shaft. The standard cross section of the key is 14 x 9 mm.
• The key is made of commercial steel (Syt = Syc = 230 N/mm) and the factor of safety is 3. Determine the length of the key on the basis of shear and compression considerations, if 15 kW power at 360 rpm is transmitted through the keyed joint.
• i. Calculate the permissible compressive and shear stress. (2m) Calculate the torque transmitted by the pulley. (2m) Determine the length of the key on the basis of shear considerations. (2m) Determine the length of the key on the basis of compression considerations. (2m) V.
• Based on your calculation, which length will be deriving factor in your key design? Why? (2m)

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Answer 2

Answer:

★flat key is used to connect a pulley to a 45 mm diameter shaft. The standard cross section of the key is 14 x 9 mm.

★The key is made of commercial steel (Syt = Syc = 230 N/mm) and the factor of safety is 3. Determine the length of the key on the basis of shear and compression considerations, if 15 kW power at 360 rpm is transmitted through the keyed joint.

★i. Calculate the permissible compressive and shear stress. (2m) Calculate the torque transmitted by the pulley. (2m) Determine the length of the key on the basis of shear considerations. (2m) Determine the length of the key on the basis of compression considerations. (2m) V.

★Based on your calculation, which length will be deriving factor in your key design? Why? (2m)

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