A flat silver strip of width 1.5cm and thickness 1.5mm carries a current of 150A. A magnetic field of 2T is applied perpendicular to the flat face of the strip. The emf developed across the width of the strip is measured to be 17.9uV. Calculate the free electron density in the silver.
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Answer:
Explanation:
e use n=
Vle
Bi
∴V=
nle
iB
=
(8.47×10
28
/m
3
)(150μm)(1.6×10
−19
C)
(23A)(0.65T)
=7.4×10
−6
V
n=BiVle
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