A flight take offone hour late from Ahmedabad airport. It has to increase its speed 100 km/hr to reach 1200
km away at a time. Find is original speed.
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Let original speed be x.
time = distance/speed
original time = 1200 / x
new time = 1200 / x+100
1200 / x - 1200 / x + 100 = 1
1200 (1 / x - 1 / x + 100)=1
1200 (x + 100 - x / x* +100x) =1 here x* is x square.
120000 = x * + 100x
x * + 100x -120000 =0
therefore by solving equation
x = 300 km/hr
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