Question

a floiring tiles has the shape of parrallelogram whose base is 24 cm and corresponding height is 10 cm how many such tiles are required to cover a floir of area 1080cm2

Answer 1

Base = 24cm
height =10cm
area= 1080cm square .

so area of that tile = Base ×height
= 24×10
= 240 cm square
now tiles required = 1080÷240
= 4.5
theirfore required tiles= 4.5 tiles

Answer 2

Total area of room = 1080m²

Base of "one" tile = 24cm

Height of "one" tile = 10cm

Area of "one" tile = Base×height

$\huge\purple{24 \times 10}$

$\huge\purple{240 {cm}^{2} }$

$\huge\purple{0.024 {m}^{2} }$

$\red{no. \: of \: tiles \:  =  \frac{area \: of \: room}{area \: of \: one \: tile} }$

$\huge\orange{ \frac{1080}{0.024} }$

$\pink{so... \: 45000 \:tiles \: are \: needed }$