Question

A floooring tile has a shape of a parallelogram whose base is 28cm and the corresponding height is 20 cm how many such tiles are required to cover a floor of an area 2.8m² ?​

Answer 1

Answer:

Area of tile = b*h 36 * 12 = 432cm^ 432cm = 432/100 cm^ Area of floor = (108 * 108) m^ No. Of tiles required = (108 × 108)/ (432/100) (108*108*100)/432 (108*100)/4 27*100 2700 tiles

Answer 2

Answer:

50 tiles are required to cover the floor

Step-by-step explanation:

height of the tile= 20 cm

base of the tile = 28 cm

area of the parallelogram tile = h × b

= 20 × 28

= 560cm²

area of the floor = 2.8m² = 2.8× 10000

= 28000cm²

no. of tiles required:

$\frac{28000}{560}$

$= 50$

50 tiles are required to cover the floor

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