Question

A floor 4.5m long and 3.6 m wide is to be covered with tiles . A 6cm square tiles costs rupees 23.25. What will be the cost to cover the floor with these tiles?

Answer 1

Given :–

• Length of floor = 4.5m long
• Breadth of floor = 3.6m wide
• A 6cm square tile costs rupees 23.25

To Find :–

• Cost to cover the floor with these tiles.

Solution :–

Area of the floor = Length of floor × Breadth of floor

→ 4.5m × 3.6m

First, convert meter into cm.

For converting,

We know that, 1m = 100cm

So, for converting we have to multiply both the length and breadth with 100.

Therefore,

• Length = 4.5 × 100 = 450
• Breadth = 3.6 × 100 = 360

Now, we have to find the area of the floor.

→ 450 × 360

→ 162000cm²

• Area of the floor = 162000cm²

Now, we have to find the area of a tile,

Area of a square tile = (side)²

→ side × side

• Side of square tile is given = 6cm.

→ 6 × 6

→ 36cm

• Area of a tile = 36cm.

Now, we have to find number of tiles,

So for finding number of tiles, we divide the area of the floor by area of a tile.

Number of tiles = $\frac{area \: of \: the \: floor}{area \: of \: a \: tile }$

→ $\frac{\cancel{162000}}{\cancel{36}}$

Cut the numbers by 2.

→ $\frac{\cancel{81000}}{\cancel{18}}$

Again cut the numbers by 2.

→ $\frac{\cancel{40500}}{\cancel{9}}$

Now, cut the numbers by 3.

→ $\frac{\cancel{13500}}{\cancel{3}}$

Again cut the number by 3.

→ 4500

• Number of tiles = 4,500
• Cost of 1 tile = Rs. 23.25 [Given]

So,

Cost of 4,500 tiles = Cost of 1 tile × Number of tiles

→ 23.25 × 4500

→ Rs. 1,04,625

Hence,

• Cost of 4,500 tiles = Rs. 1,04,625.