Question

a floor consists of 2000 tiles each tile is the shape of rhombus having sides of 8 cm and altitude of 5 cm . find the cost of tiling at the rate of 50 paise per cm2​

Answer 1

Question :-

A floor consists of 2000 tiles each tile is the shape of rhombus having sides of 8 cm and altitude of 5 cm. Find the cost of tiling at the rate of 50 paise per cm^2

$\large\underline{\sf{Solution-}}$

Given that,

Side of rhombus tile = 8 cm

Altitude of rhombus tile = 5 cm

We know,

Area of rhombus whose side (b) and altitude (h) is known, is given by

$\boxed{\sf{ \:\rm \: \: Area_{(rhombus)} \: = \: side \: \times \: altitude \: }}$

So, on substituting the values, we get

$\rm \: Area_{( \: 1 \: tile \: )} = 8 \times 5 = 40 \: {cm}^{2}$

As, it is given that floor consists of 2000 tiles of rhombus shape.

So, Area of 2000 tiles is given by

$\rm \: Area_{( \: 2000 \: tile \: )} = 2000 \times 40 \: = 80000 \: {cm}^{2}$

Now, Further given that

$\rm \: Cost \: of \: tiling \: {1 \: cm}^{2} = 50 \: paisa$

So,

$\rm \: Cost \: of \: tiling \: {80000 \: cm}^{2} = 80000 \times 50 = 4000000 \: paisa$

We know,

Re 1 = 100 paisa

So,

$\rm \: Cost \: of \: tiling \: {80000 \: cm}^{2} = \:Rs \: 40000 \:$

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Additional Information :-

$\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}$

Answer 2

Question:-

A floor consists of 2000 tiles each tile is the shape of rhombus having sides of 8 cm and altitude of 5 cm. Find the cost of tiling at the rate of 50 paise per cm².

Given:-

• A floor consists of 2,000 tiles each tile is the shape of rhombus having sides of 8 cm and altitude of 5 cm.

To Find:-

• The cost of tiling at the rate of 50 paise per cm².

Solution:-

Area of each tile which is in the shape of rhombus

= side × altitude

= 8 × 5

= 40cm².

Area of 2,000 tiles

= 2,000 × 40

= 80,000cm².

Cost of tiling at the rate of 50 paise per cm²

= 50 × 80,000

= 4,00,00,00 paise

$\sf \large = \frac{4,00,00,{{ \cancel{00}}}}{1{{ \cancel{00} }}}$

= ₹40,000.

Answer:-

$\sf \large \red{Cost \: of \: tiling \: at \: the \: rate \: of \: 50 \: paise \: per \: cm {}^{2} =₹40 ,000.}$

Hope you have satisfied. ⚘