Question

A floor consists of 2000 tiles each tile is the shape of rhombus having sides of 8 cm and altitude of 5 cm . find the cost of tiling at the rate of 50 paise per cm2

:-)​

Answer 1

Answer:

Given :-

Floor consists of = 2000 tiles in shape of Rhombus

Sides = 8cm and Altitude = 5cm

Cost of tiling = 50 Paise per cm square

To find :-

Cost of Tiling

Sol :-

First we will find the area of 1 tiles

Sides is 8cm and Altitude is 5cm ( Given )

Area of Rhombus = Base × Height

( Sides including bases which is 8 cm )

Area of Rhombus = 8 × 5

Area of Rhombus = 40 cm square

Area of such 2000 Tiles = 2000 × 40

Area of 2000 Tiles = 80,000 cm square

Cost of Tiling = 50P per cm square ( Given )

Cost of 2000 Tiles will be = 80000 × 50

Cost of 2000 Tiles = 40,00,000 Paise

Cost of 2000 Tiles in Rupees will be :-

4000000/100 ( 1 Rupees = 100 Paise )

Therefore , Cost of tiling is = 40,000 Rupees

Answer 2

Step-by-step explanation:

Given:-

A floor consists of 2,000 tiles each tile is the shape of rhombus having sides of 8 cm and altitude of 5 cm.

To Find:-

The cost of tiling at the rate of 50 paise per cm².

Solution:-

Area of each tile

$\bf= side × altitude \\ \bf= 8 × 5 \\ \bf= 40cm².$

Area of 2,000 tiles

$\bf= 2,000 × 40 \\ \bf= 80,000cm².$

Cost of tiling at the rate of 50 paise per cm²

= 50 × 80,000

= 4,00,00,00 paise

$\bf{= \frac{4,00,00,{{ \cancel{00}}}}{1{{ \cancel{00} }}}}$

= ₹40,000.

$\boxed{\bf \red{Cost \: of \: tiling \: at \: the \: rate \: of \: 50 \: paise \: per \: cm {}^{2} =₹40 ,000.}}$