A floor having length of 72ft and width of 36ft needs to be covered with square tiles of edge length 2 1/4 ft. The same tiles need to be placed all around this floor. How many tiles will be needed in All? ALSO the boundary tiles need to coloured black. If 1 bucket of black paint can color 6 4/5 tiles , then find the number of buckets required?
The answer given 512 tiles for floor 100 tiles for boundary , 14 12/17 buckets of paint. Please give steps to get this answer
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here ur answer goes...
here is ur solution..
if
if the length of the floor= 72 ft
and the width= 36ft
so area of the
floor = 72x36 = 2952 f. square
edge length of tiles=2 1/4 = 5/4.f
if the length of tile is = 1f
then width = √[ (5/4) square -1)]
=√[25/16-1]
=√[(25-16)/16)]
=√[9/16]
=3/4f
so the area of tiles= 1×3/4=3/4 f
then the number of tiles = 2952÷3/5=3456
The number of tiles = 34596 is ans 1
The boundary tiles
in the length of both side is
(72+72)/1=144
and in width ......in above pic
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