a floor is 10cm long and 8cm wide. it is surrounded by an uniform width verandah all around from outside.if the area of verandah is 40 square m.Then find the width of the varandah
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let the width of the veranda be x
of the rectangle without veranda:-
area = 10 x 8 = 80
of the rectangle with veranda:-
length = 10+2x
breadth = 8 + 2x
area = (10+ 2x )(8 + 2x )
= 80 + 20x + 16x + 4x^2
= 4x^2 + 36x + 80
now
area of the veranda = 40
area of the floor with veranda
- area of floor without veranda = 40
4x^2 + 36x + 80 - 80 = 40
4x^2 +36x -40 = 0
x^2 + 9x - 10 =0
x^2 + 10x- x - 10 = 0
x ( x + 10) - (x + 10) = 0
(x - 1)(x + 10) = 0
therefore
either
x-1 = 0
x = 1
or
x+10 = 0
x = -10
since width cannot be negative.
so
x = 1
the width of the veranda = 1m sq
of the rectangle without veranda:-
area = 10 x 8 = 80
of the rectangle with veranda:-
length = 10+2x
breadth = 8 + 2x
area = (10+ 2x )(8 + 2x )
= 80 + 20x + 16x + 4x^2
= 4x^2 + 36x + 80
now
area of the veranda = 40
area of the floor with veranda
- area of floor without veranda = 40
4x^2 + 36x + 80 - 80 = 40
4x^2 +36x -40 = 0
x^2 + 9x - 10 =0
x^2 + 10x- x - 10 = 0
x ( x + 10) - (x + 10) = 0
(x - 1)(x + 10) = 0
therefore
either
x-1 = 0
x = 1
or
x+10 = 0
x = -10
since width cannot be negative.
so
x = 1
the width of the veranda = 1m sq
joe30:
so taking roots of the equation
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0
check out this..but I'm not sure okk.
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