Math, asked by saumya29, 1 year ago

a floor is 10cm long and 8cm wide. it is surrounded by an uniform width verandah all around from outside.if the area of verandah is 40 square m.Then find the width of the varandah

Answers

Answered by maria9
2
let the width of the veranda be x
of the rectangle without veranda:-
area = 10 x 8 = 80
of the rectangle with veranda:-
length = 10+2x
breadth = 8 + 2x
area = (10+ 2x )(8 + 2x )
= 80 + 20x + 16x + 4x^2
= 4x^2 + 36x + 80
now
area of the veranda = 40
area of the floor with veranda
- area of floor without veranda = 40
4x^2 + 36x + 80 - 80 = 40
4x^2 +36x -40 = 0
x^2 + 9x - 10 =0
x^2 + 10x- x - 10 = 0
x ( x + 10) - (x + 10) = 0
(x - 1)(x + 10) = 0
therefore
either
x-1 = 0
x = 1
or
x+10 = 0
x = -10
since width cannot be negative.
so
x = 1
the width of the veranda = 1m sq

joe30: so taking roots of the equation
joe30: x=1 and x= -10
maria9: yes
joe30: x= -10 not possible since quantity is lengtg
joe30: length
joe30: hence directly you gotta take x=1
maria9: yes
joe30: hey maria how u took the length same
joe30: cause acc to question its not said its same in both
joe30: there its written floor is surrounded all round by verandah.
Answered by joe30
0
check out this..but I'm not sure okk.
Attachments:

saumya29: ok
joe30: how did u get length 1p
joe30: 10
joe30: the floor's length is 10 m its given.
joe30: so how u made it length of the verandah.
joe30: cause in ques its written verandah surrounding floor all around.
joe30: so diagram will be of two rectangles..bigger rectangle of whole including the floor.
joe30: and smaller rectangle inside the bigger one of only floor.
saumya29: i didn't understand what u want to say
joe30: I'm asking her..uhh u make a diag acc to the info of the ques..u will understand
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