Question

A floor is 12.2 m long and 8.1 m wide. A 9 CM square tile costs 27.35 rupees. What is cost to cover the floor with these tiles...
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Answer 1

Heyy Army!!..Your answer is.....

Answer:

The length of the floor = 12.2m

= 12.2×100= 1220cm

Width of the floor= 8.1m

= 8.1×100= 810cm

Area of the floor = (1220 × 810)cm^2

=988200 cm^2

Side of the square tile= 9cm

Area of one square tile= 9×9 cm^2

No of tiles required to cover the floor= Area of the floor / Area of one tile

= 12200

Now, the cost of the tile= 27.35

Cost of 12200 tiles= 27.35×12200

= 333670 rupees

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Answer 2

Answer:

The length of the floor = 12.2m

=12.2*100=1220cm

Width of the floor=8.1m

=8.1*100=810cm

Area of the floor=(1220*810)cm^2

=988200 cm^2

Side of the square til=9cm

Area of one square tile=9*9cm^2=81cm^2

No.of square tiles required to cover the floor=

Area of the floor/Area of one tile

=12200

Now,the cost of the tile=27.35

Cost of 12200 tiles=12200*27.35

=33670 rupees

Hope this will help you

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