Question

A floor is 4.5 m long and 3.6 m wide. A 6 cm square tile costs Rs.23.25. What will be the cost to cover the floor with these tiles?​

Answer 1

The cost to cover the floor with these tiles is Rs. 627750.

✥ Given: A floor is 4.5 m long and 3.6 m wide. A 6 cm square tiles cost Rs. 23.25

⛄ To find: What will be the cost to cover the floor with these tiles?

★ Solution-

A floor is 4.5 m long and 3.6 m wide.

The area of the floor is

$a = l \times b$

$a = 4.5 \times 3.6$

$a = 16.2 {m}^{2}$

Converting m into cm,

$1m = 100cm$

$1 {m }^{2} = 10000cm ^{2}$

༒ So,

$16.2 m^{2} = 16.2 \times 10000 = 162000cm ^{2}$

Area of square tile is 6 cm².

Number of tiles required to cover the floor is,

$n = \frac{area \: of \: floor}{area \: of \: tile}$

$n = \frac{162000}{6}$

$n = 27000$

Cost of 1 tile is Rs.23.25.

$cost \: of \: 27000 \: tile \: is \: 27000 \times 23.25 = rs. \: 627750$

Therefore, The cost to cover the floor with these tiles is Rs.627750.