Question

A floor is 4.5 m long and 3.6 m wide. A 6 cm square tile costs Rs.23.25. What will be the cost to cover the floor with these tiles?​

Answer 1

$\sf{Given :-}$

• A floor is 4.5 m long and 3.6 m wide. A 6 cm square tiles cost Rs. 23.25

$\sf{To \: find :-}$

• What will be the cost to cover the floor with these tiles?

$\sf{Solution:-}$

A floor is 4.5 m long and 3.6 m wide.

The area of the floor is $\sf{A=l\times b}$

$\sf{A=4.5\times 3.6}$

$\sf{A=16.2m^2}$

A floor is 4.5 m long and 3.6 m wide.

Now Converting m into cm,

1 m = 100 cm

1 m² = 10000 cm²

$\small \sf{So,16.2m^2=16.2×10000=162000 \;cm^2}$

Area of square tile is 6 cm².

Number of tiles required to cover the floor is

$\sf \small{N = \frac{Area \: of \: floor}{Area \: of \: tile} }$

$\sf \small{N = \frac{162000}{6} }$

$\sf \small{N = 27000 }$

Cost of 1 tile is Rs.23.25.

$\sf \small{Cost \: of \: 27000 \: tile \: is \: 27000 \times 23.25 = Rs.627750}$

So, The cost to cover the floor with these tiles is Rs.627750.