Question

A floor is 4.5 m long and 3.6 m wide. A 6 cm square tile costs Rs.23.25. What will be the cost to cover the floor with these tiles?​

Answer 1

Answer:

The cost to cover the floor with these tiles is Rs.627750.

Step by step explanation -

Given : A floor is 4.5 m long and 3.6 m wide. A 6 cm square tiles cost Rs. 23.25

To find : What will be the cost to cover the floor with these tiles?

Solution :

A floor is 4.5 m long and 3.6 m wide.

The area of the floor is A=l\times bA=l×b

A=4.5\times 3.6A=4.5×3.6

A=16.2m^2A=16.2m

2

Converting m into cm,

1 m = 100 cm

1 m² = 10000 cm²

So, 16.2m^2=16.2\times 10000=162000cm^216.2m

2

=16.2×10000=162000cm

2

Area of square tile is 6 cm².

Number of tiles required to cover the floor is

n=\frac{\text{Area of floor}}{\text{Area of tile}}n=

Area of tile

Area of floor

n=\frac{162000}{6}n=

6

162000

n=27000n=27000

Cost of 1 tile is Rs.23.25.

Cost of 27000 tile is 27000\times 23.25=Rs.62775027000×23.25=Rs.627750

Therefore, The cost to cover the floor with these tiles is Rs.627750.

Answer 2

❥SOLUTION

GIVEN :

Length of rectangular room =4.5 m

Breadth of rectangular room=3.6 m

TO FIND :

No.of tiles required to cover the room and what will be the cost .

cost of 1 tile =23.25 rupees

SOLUTION:

Area of rectangular room =length × breadth

=4.5 m × 3.6 m

=16.2 m × 100 cm

=16200 cm

Area of 1 tile = side × side

= 6×6 =36 cm

No.of tiles needed to cover the room = 16200÷36 cm = 450 tiles

cost of tiling = 450× 23.25 rupees

total cost = 10,462.5 rupees

HOPES, IT'S HELPFUL TO YOU BRO.(◠‿・)—☆