Question

A floor is 4.5 m long and 3.6 m wide is to be covered with tiles. A 6 cm square tile costs 23.25. What will be the cost to cover the floor? ​

Answer 1

Answer:

Length of the floor = 4.5 m = (4.5 × 100) cm = 450 cm Width of the floor – 3.6 m – (3.6 × 100) cm = 360 cm ∴ Area of the floor – (450 × 360) cm2 = 162000 cm2  Side of a square tile = 6 cm ∴ Area of one square tile = (6 × 6) cm2 = 36 cm2 Number of tiles required to cover the floor = Area of floor/ Area of one tile = 4500 Now, cost of one tile = ₹ 23.25 ∴ Cost of 4500 tiles =₹ (23.25 × 4500) = ₹ 104625Read more on Sarthaks.com - https://www.sarthaks.com/787662/floor-long-and-wide-square-tile-costs-what-will-the-cost-to-cover-the-floor-with-these-tiles

Answer 2

Answer:

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