Math, asked by sureus9486, 1 year ago

A floor is 4.5 m long and 5.6 m wide.A 6 cm long tile costs rs 23.25 what will be the cost to cover the floor with these tiles

Answers

Answered by Ojusoni
1

Area of the floor is length*breath

So, 4.5m*5.6m = 25.2msqu

Convert 6cm into m = 6*0,01 = 0.06m

25.2msqu÷0.06m = 420m

Rs of 0.06m = 23.25$

So 420m*23.25 = 9870$

Answered by harisreeps
0

Answer:

A floor 4.5m long and 5.6m wide is to be covered with tiles. A 6cm square tile costs rs.23.25, the cost to cover the floor with these tiles is 162750 rupees

Step-by-step explanation:

The length of the floor l=4.5m=450cm

the breadth of the floor b=5.6m=560cm

since the floor is a rectangle the total area of the floor is A=l*b

A=450*560=252000cm^{2}

the side of the square tile a=6cm

since the tile is a square the area of one tile A=a^{2}

A=6*6=36cm^{2}

now the number of tiles is given as the area of the floor divided by the area of one tile

⇒  \frac{450*560}{36}=7000

the cost of one tile is 23.25rs/-

now the total cost of the tile is the product of the total number of tiles and the price of one tile

7000*23.25=162750rs/-

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