A floor is 40m long and 15m broad. It is covered with tiles, each measuring 60 cm by 50 cm. Find the number of tiles required to cover the floor.
Answers
Answered by
122
Floor?
Length =40m=40*100=4000
Breadth==15*100=1500
Area =4000*1500=6000000
Tiles,
Length=60cm
Width=50
Area=50*60=3000cm
No of tiles required=6000000/3000=2000
Length =40m=40*100=4000
Breadth==15*100=1500
Area =4000*1500=6000000
Tiles,
Length=60cm
Width=50
Area=50*60=3000cm
No of tiles required=6000000/3000=2000
Answered by
57
change m to cm 40 ×100 =4000cm
15 ×100 =1500cm
area of floor = 4000cm × 1500cm = 6000000cm ^2
area of a tile = 50 cm ×60 cm = 3000cm^2
No of tiles = area of floor / area of a tile
= 6000000cm ^2 / 3000cm^2 = 2000
=2000 tiles are required to cover the floor
15 ×100 =1500cm
area of floor = 4000cm × 1500cm = 6000000cm ^2
area of a tile = 50 cm ×60 cm = 3000cm^2
No of tiles = area of floor / area of a tile
= 6000000cm ^2 / 3000cm^2 = 2000
=2000 tiles are required to cover the floor
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