Question

A floor is 40m long and 15m broad. It is covered with tiles, each measuring 60cm by 50cm. Find the number of tiles required to cover the floor. *​

Answer 1

Answer:

dei baadu.. gaaju thailee

Answer 2

Answer:

2000 tiles

Step-by-step explanation:

Given,

Length of the floor = 40 m = 4000cm

Breadth of the floor = 15 m = 1500cm

Therefore,

Area of the floor in cm = Length × Breadth

= 4000 cm × 1500 cm

$= 6000000 {cm}^{2}$

Now,

We know that,

Dimensions of the tiles = 60 cm and 50 cm

Therefore,

Area of the tiles = Length × Breadth

= 60 cm × 50 cm

$= 3000 {cm}^{2}$

According to the question,

Now,

Number of tiles required to cover the floor are

$= \frac{area \: of \: the \: floor}{area \: of \: the \: tiles}$

$= \frac{6000000 {cm}^{2} }{3000 {cm}^{2} }$

= 2000

Hence,

Required number of tiles to cover the floor is 2000 (Ans)