a floor is 5 long and for M weird a square carpet of side 3 metre is lead on the floor find the area of the floor that is not carpeted
Answers
Answer:
Speed(S1) = 75 km/hr
Distance(D1) = 30 km
In second case:
Speed(S2) = 60 km/hr
Distance(D2) = 50 km
Formula:
Average Speed = (Total Distance/Total Time)
Time = Distance/Speed
Calculation:
Total Distance = 30 + 50 = 80 km
According to the question:
In first case:
Time = = hrs
In second case,
Time = = hrs
Total Time = + = = hrs
Average Speed = (Total Distance/Total Time)
Average Speed = 80 × = 64.86 = 64.9 km/hr (approx.)
∴ The average speed of whole journey is 64.9 km/hr.
Given :
Length of the floor is 5m
The breadth of the floor is 4m
So, ( applying ar. l×b )
ar. of floor =4m×5m=20m^2
. Side of the carpet is 3m
So, (applying ar. of sq. =side×side(s))
area of carpet=3m×3m=9m^2
.
To find the area of the floor that is not carpeted or (uncarpeted) we will (−) minus the ar. of the floor from ar. of carpet
area which is not carpeted or( uncarpeted ) =20m
2 −9m^2
=11m^2
.
Hence, answer Is 11m^2
.