Math, asked by adityathakur1458, 17 days ago

A floor is 5m long and 4m wide. A square carpet of side 3m is laid on the floor. find the area of the floor that is not carpeted

Answers

Answered by alexryv555
2

Answer:

11

Step-by-step explanation:

area of floor = 5*4=20

area of carpet=3*3=9

therefore , 20-9=11

pls mark as brainlist

Answered by Anonymous
35

Given

  • The floor is 5m long and 4m wide

  • A square which is carpeted is of side 3m

To find

  • The area of floor that is not carpeted

Solution

{ \underline{ \underline{ \boxed{ \bf{Understanding \: the \: question}}}}}

In the given question it has written to find the area of the floor which is not carpeted and it has given the length and breadth of the floor and the side of the square carpet and to find the answer we have to use one formula and after using the formula we have to to find the area of the floor and the area of the square carpet then we will get the whole answer.

Diagram

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 5 m}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 3 m}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}

[Note:- Kindly see the diagram on the web page]

{ \bf { \dag{ \purple{\boxed{ \mathfrak{Formula \ used}}}}}}

\;\boxed{\sf{\pink{Area \: of \: floor  \:  -  \: Area \: of \: carpet =  Area \: of \: floor \: that \: is \: not \: carpeted}}}

\;\boxed{\sf{\blue{Area_{\:(rectangle)} = Length \times Breadth}}}

\;\boxed{\sf{\red{Area_{\:(square)}  = side\times side}}}⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

:  \implies Area of floor \mapsto 5m × 4m

⠀⠀⠀⠀⠀⠀⠀⠀

:  \implies  20  \sf{m}^{2}

⠀⠀⠀⠀⠀⠀

:  \implies Area of carpet \mapsto 3m × 3m

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

:  \implies 9  \sf{m}^{2} ⠀⠀⠀⠀⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

:  \implies  20  \sf{m}^{2} - 9

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

:  \implies { \underline{ \underline { \boxed{ \pink{ \mathfrak{Area \leadsto11  \sf{m}^{2}}}}}}}

⠀⠀⠀⠀

•°• Hence, verified! that the area which is not carpeted is 11  \sf{m}^{2}

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀⠀⠀⠀

Similar questions