Question

A floor is 5m long and 4m wide . A square carpet of sides 3m is laid on the floor .find the area of the floor that is not carpeted??

Answer 1

Answer:

• Area of floor that is not carpeted is 11 m².

Step-by-step explanation:

To find:-

• Area of floor that is not carpeted.

Solution:-

Given that,

A floor is 5 m long and 4 m wide. A square carpet of sides 3 m is laid on the floor.

Side of carpet = 3 m.

• Shape of carpet is square.

Area of square = Side × Side

$\longrightarrow$ 3 × 3

$\longrightarrow$ 9

Area of carpet is 9 m².

Length (given long) of floor is 5 m.

Breadth (given wide) of floor is 4 m

• Length and breadth is given. So, the shape of floor is rectangular.

Area of rectangle = length × breadth

$\longrightarrow$ 5 × 4

$\longrightarrow$ 20

Area of floor is 20 m².

Area of floor that is not carpeted = Area of floor - Area of carpet.

$\longrightarrow$ 20 - 9

$\longrightarrow$ 11

Therefore,

Area of floor that is not carpeted is 11 m².

Answer 2

Answer:

$\huge \bf \: given$

• Length of floor = 5 m
• Breadth of floor = 4 m
• Side of square carpet = 3 m

$\huge \bf \: to \: find$

Area of floor that is not carpeted

$\huge \bf \: solution$

For this we have to find the area of floor and the area of square as well.

$\huge \ \bf \: {area \small rectangle = l \times b}$

$\sf \: area \: of \: floor \: = 5 \times 4$

$\sf \: area \: of \: floor = 20 {m}^{2}$

$\huge \bf \: area \small square = \huge \bf \: s\times s$

$\sf \: area \: of \: carpet \: = 3 \times 3$

$\sf \: area \: of \: carpet \: = 9 {m}^{2}$

$\sf \: remaining \: area \: = 20 - 11$

$\huge \fbox {remaining area = 9 \: m}$