Question

A floor is 6 m long and 3 m wide. A
rectangular carpet of length 3.5 m and
width 2 m is laid on the floor. Find the
area of the floor that is not carpeted.​

Answer 1

$\huge\rm\orange{anSwer:}$

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$\bf{{\underline{Given}}:}$

• A floor is 6 m long and 3 m wide. A rectangular carpet of length 3.5m and width 2m is laid on the floor.

$\bf{{\underline{To~find}}:}$

• The area of the floor that is not carpeted.

$\bf{{\underline{Here}};}$

$\sf Area \: of \: the \: floor \: that \: is \: not \: carpeted = \: \: \: \: \: \: \: \: \: \\ \sf \orange{(area \: of \: the \: floor) - (area \: of \: the \: carpet)}$

$\bf{{\underline{Area~of~a~rectangle}}:}$

$\sf length \times breadth \\ \: \: \: \: \: \: \: \: \sf \implies \orange{l \times b}$

$\bf{{\underline{Area~of~the~floor}}:}$

$\bf{Here}: \: \sf{l = 6m \: \: \: b = 3m} \\ \sf \implies l \times b \: \: \: \: \: \: \\ \sf \implies 6 \times 3 \: \: \: \: \: \\ \sf \implies \orange{ \underline{ \boxed{ \bf {18m}^{2} }}}$

$\bf{{\underline{Area~of~the~carpet}}:}$

$\bf{Here}: \: \sf{l = 3.5m \: \: \: b = 2m} \\ \sf \implies l \times b \: \: \: \: \: \: \\ \sf \implies 3.5 \times 2 \: \\ \sf \implies \orange{ \underline{ \boxed{ \bf {7m}^{2} }}} \: \: \:$

$\bf\therefore{{\underline{Area~of~the~floor~not~carpeted}}:}$

$\sf (area \: of \: the \: floor) - (area \: of \: the \: carpet) \\ \sf \implies {18m}^{2} - {7m}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf \implies \orange{ \underline{ \boxed{ \bf {11m}^{2} }}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$