Question

A floor is 80 m long and 60 m broad. It is covered with tiles, each

measuring 160 cm by 150 cm. Find the number of tiles required to cover

the floor.
Step by step pls,​

Answer 1

Answer:

There are 2 × 10³ or 2000 tiles required to cover the floor.

Step-by-step explanation:

Given, the floor dimension is 8,000 × 6,000 cm

the tile dimensions is 160 × 150 cm

Solution, area of floor = l × b

= 8,000 × 6,000

= 48,000,000

= 4.8 × 10⁷ cm²

Similarly, area of tile = l × b

= 160 × 150

= 24,000

= 2.4 × 10⁴ cm²

Now, the number of tiles = Ar. of floor/Ar. of tile

= 4.8 × 10⁷/2.4 × 10⁴

= 2 × 10³

Answer 2

What we have to do ?

Here, we have given a floor whose length is 80 m and breadth is 60 m. This floor is covered with tiles. The tile is 160 cm long and 150 cm broad.

We have asked to find out the number of tiles.

For that, First we will find out the Area of floor and then the area of one tile. After that we will divide the Area of floor by Area of 1 tile then, we get our answer.

${\underline{\bf{Step \: by \: Step \: Solution :}}}$

$:\implies\sf Area \: of \: Floor = Length \times Breadth$

• Length → 80 m
• Breadth → 60 m

$:\implies\sf Area \: of \: Floor = 80 \times 60$

$\dashrightarrow\:\:\sf Area = 4800 \: m^{2}$

${\boxed{\sf {Area \: of \: floor = 4800 \: m^{2}}}}$

Now,

$\dashrightarrow\:\:\sf Area \: of \: a \: Tile = Length \times Breadth$

• Long → 160 cm or 16 m
• Broad → 150 cm or 15 m

We will take the measurements in metres as the measurements of floor is also given in metres.

$\dashrightarrow\:\:\sf Area \: of \: a \: Tile = 16.0 \times 15.0$

$:\implies\sf Area = 240 \: m^{2}$

Therefore, Number of tiles used :

$\longrightarrow\tt{ Number \: of \: tiles = \dfrac{Area \: of \: Floor}{Area \: of \: 1 \: Tile}}$

$\longrightarrow\tt{ Number \: of \: tiles = \dfrac{4800}{240}}$

$\sf \longrightarrow \: Tiles \: = {\dfrac{ \cancel{4800}^{ \: \: 20} }{ \cancel{240}^{ \: \: 1} } \: }$

$\dashrightarrow\:\:\sf Tiles = 20$

Hence,

$:\implies \underline{\boxed{\sf Number \: of \: Tiles = 20}}$