Math, asked by sanjaym875, 1 year ago

A floor is made up of 400 Rhombus shaped tiles with diagonal measuring 18 cm and 12 CM as well as 250cm trapezium shaped tiles the parallel sides measuring 10 cm and 12 cm and height is 8 cm find the area of the floor also find the cost of polishing the floor if the cost of polishing is rupees 200 per metre square

Answers

Answered by Rudraji
74
Area of rhombus tiles
= 1/2 * d1*d2 *400
= 1/2 * 18 *12 *400
=12*9*400
=108*400
=43200 cm2

Area of trapezium tiles
= 1/2* (d1 + d2) * h * 250
= 1/2 * (10 + 12) *8 * 250
= 1/2 *22 * 8 * 250
= 11 * 8 * 250
= 22000 cm2

Total area = 43200 + 22000
=65200 cm2
= 65200/100*100 m2
= 6.52 m2

Total cost = 6.52 * 200
= Rs 1304

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Answered by narangdinesh954
3

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