Question

A floor is triangular in shape. The side of the triangle are 26cm, 28 cm and 30 cm. Find the cost of polishing the floor as the rate of 50 per cm square ​

Answer 1

Answer:

First find area of triangle side are 26.28.30

Use heron's formula for finding area of triangle

Area of triangle = 336 cm sq.

Cost of polishing of floor at rate of 50 per cmsq.

=. 50 *336

= 16800 ans

Answer 2

Answer:

Step-by-step explanation:

given,

a = 26

b=28

c=30

s = $\frac{a + b + c}{2}$

s=$\frac{26 +28+30}{2}$

s=$\frac{84}{2}$ =42

by applying heron s formulae = $\sqrt{s (s-a)(s - b)(s - c)}$

                                                   =$\sqrt{42(42 -26)(42-28)(42-30)}$

                                                   =$\sqrt{42 * 16 * 14 * 12$

                                                   =√42×16×14×12

                                                   =√2×3×7×2×2×2×2×2×7×2×2×3

                     taking common   =  7×2×3×2×2×2                              

              area of triangle   = 336 $cm^{2}$

       cost of polishing $cm^{2}$  =  50 rupees

cost of polishing a floor of triangle = 336 × 50

                                                             =16800 rupees

hence , cost of polishing triangular floor is rupees 16800  

PLEASE MARK IT AS BRAINLIEST