Question

a floor measuring 2m by 1.5m is to be covered with tiles measuring 25cm by 25cm find the number of tiles required to cover the tiles at rupee 420 per dozen​

Answer 1

Answer:  48 tiles    rs 1680

Step-by-step explanation:

first area of floor-

    200cm*150cm=30000cm

area of tile-

      25*25=625

for no of tiles divide-

30000/625= 48 tiles

if one dozen=Rs 420

48 = 4 dozen

4 dozen = 4*420= Rs 1680

Answer 2

Hey Buddy

Here's The Answer

______________________

Dimensions of floor :

length ( L ) = 2 m

breath ( B ) = 1.5 m

Dimensions of tile :

length ( l ) = 25 cm = 0.25 m

breadth ( b ) = 25 cm = 0.25 m

Cost : 420 per dozen

12 tile = Rs. 420

1 tile = 420/12

1 tile = Rs. 35

Area of floor : Length × Breath

=> Area of floor = L × B

=> Area of floor = 2 × 1.5

=> Area of floor = 3 m²

Area of tile : length × breath

reath=> Area of floor = l × b

=> Area of floor = 0.25 × 0.25

=> Area of floor = 0.0625 m²

Total tile required to fill 3 m² Area :

Total tile = area of floor / area of tile

total tile = 3 / 0.0625

total tile = 48

Cost for 48 tile

=> Cost = 48 × 35

=> Cost = Rs. 1680

Hence, tile of worth Rs. 1680 will be required to cover the floor.

Hope It Helps ^^