Question

a floor of a building consists of 3000 tiles which are Robert shaped the diagonals of the each tile are 45 cm and 30 cm find the total cost of the polishing the floor cost per metre square is rupees 50paise​

Answer 1

Answer:-

$\bigstar$ Given:-

• d1 = 45cm
• d2 = 30cm

Number of tiles = 3000

Rate per m² = ₹ 0.50

Area of Rhombus = 1/2 × d1 × d2

= (1/2) × 45 × 30 = 675

Area of 1 tile = 675 cm² = 675/10000 m²

Area of 3000 tiles = 3000 × (675/10000)

[1cm² = 1/10000m²]

Cost of Polishing the floor = Total Area × rate

= (3000 × 675 × 0.50)/10000

= 3 × 675 × 0.50/10

= 3 × 675 × 0.05

= 0.15 × 675

= ₹ 101.25

Hence the total cost of polishing the floor = ₹ 101.25

Answer 2

$\huge\bold\green{\underline{Solution:}}$

$\bold\red{\underline{Given}}$

A floor of a building consists of 3000 tiles

The diagonal of 1st tiles=45cm

The diagonal of 2nd tiles=30cm

$\bold\orange{\underline{Find:}}$

• Total cost of polishing floor

$\bold\green{\underline{A.T.Q:}}$

• Formula used to area of tiles

$\bold\purple{\boxed{Area=\frac{1}{2}*d_1*d_2}}$

⟹Area of tiles=1/2×45×30

⟹Area of tile=45×15

⟹Area of tile=675cm²

⟹Area of all tiles=675×3000

⟹Area of all tiles=2025000cm²

Now, we have to convert area in m²

we know that, 1m=100cm •°•1m²=10000cm²

⟹Area of tiles=2025000/10000

⟹Area of tiles=202.5m²

Hence,

The total cost of polishing=202.5×50/100

The total cost of polishing=Rs.101.25