Question

a floor of building consist of 4500 tiles which are rhombus shaped and each of its diagonals are 50cm and 48cm in length. find the cost of polishing the floor if the cost of perm^2 is rs 5​

Answer 1

Answer:

Given:-

Total no. of tiles =2550

Since the tiles are in the shape of rhombus and diagonals are of length 20cm and 28cm.

Therefore,

d

1

=20cm

d

2

=28cm

Area of one tile = Area of rhombus

As we know that area of rhombus is given as-

A=

2

1

×d

1

×d

2

Therefore,

Area of 1 tile =

2

1

×20×28=280cm

2

∴ Area of 2550 tiles =2550×280=714000cm

2

=71.4m

2

Given that the cost of polishing is Rs.25 per m

2

.

Therefore,

Cost of polishing the floor =25×71.4=Rs.1785

Hence the cost of polishing the floor is Rs.1785.